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quastion - task for expert thinkers ( ip adress resolving )

Answered quastion - task for expert thinkers ( ip adress resolving )

  • Wednesday, January 30, 2013 6:21 PM
     
     
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    i have a question, please help me.
    http://www.dodaj.rs/f/3h/fp/bls8GkF/6421ass01.png    ---  see the picture

    The figure shows a diagram of the network. Each field from A to F represents one port on the router that are connected to the network.

    From the offered IP address select and enter the appropriate letter for each, so that clients on the network can communicate with each other to access the server and browse the website. Parameter write consider that the subnet mask on all subnets set to 255.255.255.0.

    ip addresses:

        192.168.1.25
        192.168.2.11
        192.168.256.1
        192.168.20.10
        192.168.10.250
        24.26.89.15
        192.168.1.52
        192.168.20.116
        192.168.1.256
        192.168.15.200
        24.26.89.251



    - A = ?
    - B = ?
    - C = ?
    - D = ?
    - E = ?
    - F = ?

    AND I WOULD BE GRATEFUL FOR AN EXPLANATION IF YOU CAN.

    or if you don't know the answer please point me to the right forum where i can ask this.

    Thanks in advance


     
    • Edited by hehehuhi111 Wednesday, January 30, 2013 7:34 PM
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  • Wednesday, January 30, 2013 8:15 PM
     
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    A homework ?

    a=192.168.10.250

    b=192.168.2.11

    c=192.168.20.10 or 192.168.20.116

    d=192.168.1.25

    f=192.168.15.200

    MCP | MCTS 70-236: Exchange Server 2007, Configuring

    Twitter - @yagmoth555 ()
    Blog: http://www.jabea.net | http://blogs.technet.com/b/wikininjas/

     
  • Wednesday, January 30, 2013 8:41 PM
     
     
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    A homework ?

    a=192.168.10.250

    b=192.168.2.11

    c=192.168.20.10 or 192.168.20.116

    d=192.168.1.25

    f=192.168.15.200

     thanks for quick reply, did you saw the picture that i linked above -

    http://www.dodaj.rs/f/3h/fp/bls8GkF/6421ass01.png

    you answered from that picture right ??

     
  • Thursday, January 31, 2013 2:05 AM
     
     
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    yes, you can't answer that without the graph :P

    MCP | MCTS 70-236: Exchange Server 2007, Configuring

    Twitter - @yagmoth555 ()
    Blog: http://www.jabea.net | http://blogs.technet.com/b/wikininjas/

     
  • Thursday, January 31, 2013 6:35 AM
     
     Answered
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      And the explanation is that a device can only communicate directly with another device in the same IP subnet. The number in the box must be in the same IP subnet as the device(s) connecting directly to it.

      Of the other addresses, 192.168.256.1 and 192.168.1.256 are illegal (a field cannot exceed 255) and 192.168.1.52 cannot be used (because it is already used by a device in the diagram).

    24.26.89.251 is a public address and could only be used on the public side of the router, not on the internal network in the diagram.

    Bill