Sharepoint 2013 user profile removal for disabled Active Directory User Account

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  Hi,

  Please refer to the following articles, you may need to tweak some PowerShell scripts to achieve your task.

  PowerShell Tools - Removing Orphaned Users from SharePoint

  Account Deletion and SharePoint 2010 User Profile Synchronization

  Inside the SharePoint 2010 My Site Cleanup Timer Job

  **Please mark as answered and/or helpful as appropriate

  Recently added Gallery: PowerShell Script for Creating Site Collection with Host Headers
  

  http://gallery.technet.microsoft.com/PowerShell-Script-for-7b319476
  

  
  

  • Edited by Mokhtar Bepari Friday, August 16, 2013 3:35 AM updated
  • Marked as answer by tracycai Sunday, August 25, 2013 6:38 AM

  Friday, August 16, 2013 3:35 AM
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  hi

  Did you find a solution.I need to do something similar

  Thursday, October 17, 2013 7:47 PM
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  I also need to know the answer to this.  I'm assuming from Bepari's response that it is not possible with off the shelf SharePoint 2013 implementation and we need to augment with PowerShell process?  Or am I just missing a configuration element of the User Profile Service???  Anyone?

  Wednesday, January 22, 2014 11:09 PM
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  There is Out-of-the-box solution for this. It is exclusion filters for a synchronization connection.

  Please see below link.

  http://social.technet.microsoft.com/Forums/en-US/32ee6549-9f45-4893-9a88-1b7b8ffa8f62/removal-of-disabled-ad-users-in-sharepoint-2010-user-profile?forum=sharepointadminprevious
  

  
  

  • Edited by Matias.Koppinen Thursday, April 3, 2014 9:07 AM
  • Proposed as answer by Martin Reichelt Tuesday, September 23, 2014 2:04 PM

  Thursday, April 3, 2014 9:06 AM
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  Matias is right. 2013 version of Exclusion Filters documentation could be found on TechNet: http://technet.microsoft.com/en-us/library/ee721049(v=office.15).aspx (see paragraph 2.2. Define exclusion filter for a synchronization connection).
  

  In your scenario you'll need create filter like this:

  "userAccountControl"

  "bit on equals"

  "2"

  • Edited by Martin Reichelt Tuesday, September 23, 2014 2:13 PM

  Tuesday, September 23, 2014 2:07 PM