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IP Range assigning... RRS feed

  • Question

  • Hi All,

    I'm a bit confused about assigning IP address from IP Ranges, I am using this scenario below to understand.

    Scenario
    Adatum.com an international IT solutions company, is launching 12 new branches in a new country where they currently have no existing branches. The sWin CIO has asked that each subnet should host at least 1000 devices.
    sWin has obtained a network address of 192.168.0.0/18. This address needs to be subnetted further. The internal subnet mask will be /22
    The company’s subnet plan allows for:
    - Router Pool: 2 router interfaces for each subnet – the first 2 IP addresses from each subnet.
    - Managed Network Device Pool: The first 20 IP addresses that follow the Router Pool are reserved for switches and other network devices
    - Server Pool: The first 20 IP addresses following the Managed Network Device Pool are reserved for servers.
    - Workstation Static Pool: The first 10 IP addresses following the Server Pool are reserved for Workstations that require static IP addresses.
    - Workstation DHCP Pool: The remaining IP addresses are reserved for automatic IP configuration
    You have been asked to use subnet 9 for your device addressing.
    Configure the first IP address from the Server Pool to Lon-DC1.
    Configure the first IP address from the Workstation Static Pool to sWinPC1.
    Configure the first IP address from the Router Pool to be the default gateway.

    So I have the IP address range as such 192.168.0.0 is the Network ID and 192.168.3.255 is the Broadcast address.

    Now can some one explain me how the IP ranges will be assigned having found the IP ranges being such that since the last borrowed bit is place holder of 4 the IP ranges will also be in 4, for example 192.168.0.0 - 192.168.0.3, which means that if I use the 9th subnet the IP Range is 192.68.0.32 - 192.168.0.35, however my teacher has explained me (which I did not understand for some reason) in a way that IP range 9th subnet will be 192.168.32.1 etc..

    I'm confused since my IP range method I have got it from a CISCO practice book, so if some one could explain how to get to understand IP range assigning, basically my question is how to know when does the subnet range changes (OR WHICH OCTET CHANGES IN THE IP RANGE) and which is the subnet range, my method or my teachers.

    Please help me understand, Thank You

    This is the practice book I have been using to understand.

    http://docdro.id/uJBGEID

    • Edited by tryllzhuud Tuesday, May 31, 2016 5:19 PM
    Tuesday, May 31, 2016 5:12 PM

Answers

  • Hi TryllZHuuD,

    >Now can some one explain me how the IP ranges will be assigned having found the IP ranges being such that since the last borrowed bit is place holder of 4 the IP ranges will also be in 4, for example 192.168.0.0 - 192.168.0.3, which means that if I use the 9th subnet the IP Range is 192.68.0.32 - 192.168.0.35

    I'm a little confuse with your requirements, could you please restate it with how many subnets you need to classify for 192.168.0.0, or how many hosts you want in each subnet?

    Best Regards,

    Anne


    Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Support, contact tnmff@microsoft.com.

    Wednesday, June 1, 2016 8:27 AM
    Moderator
  • Hi TryllZHuuD,

    Here is an example for your reference:

    C class network 192.168.0.0

    Default network mask: 255.255.255.0

    If I need to divide it into 4 (borrow 2 bits) subnets:

    Then the customer network mask is: 255.255.255.192(/26);

    Then each subnets will have (2^6)-2=62 usable hosts;

    subnet1: 192.168.0.0: from 192.168.0.1~192.168.0.62; (expect 0-63)

    subnet2: 192.168.0.64: from 192.168.0.65~192.168.0.127

    subnet3: 192.168.0.128: from 192.168.0.129~192.168.0.191

    sunbet4: 192.168.0.192: from 192.168.0.193~192.168.0.255

    Best Regards,

    Anne


    Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Support, contact tnmff@microsoft.com.

    Wednesday, June 1, 2016 8:46 AM
    Moderator

All replies

  • Hi TryllZHuuD,

    >Now can some one explain me how the IP ranges will be assigned having found the IP ranges being such that since the last borrowed bit is place holder of 4 the IP ranges will also be in 4, for example 192.168.0.0 - 192.168.0.3, which means that if I use the 9th subnet the IP Range is 192.68.0.32 - 192.168.0.35

    I'm a little confuse with your requirements, could you please restate it with how many subnets you need to classify for 192.168.0.0, or how many hosts you want in each subnet?

    Best Regards,

    Anne


    Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Support, contact tnmff@microsoft.com.

    Wednesday, June 1, 2016 8:27 AM
    Moderator
  • Hi TryllZHuuD,

    Here is an example for your reference:

    C class network 192.168.0.0

    Default network mask: 255.255.255.0

    If I need to divide it into 4 (borrow 2 bits) subnets:

    Then the customer network mask is: 255.255.255.192(/26);

    Then each subnets will have (2^6)-2=62 usable hosts;

    subnet1: 192.168.0.0: from 192.168.0.1~192.168.0.62; (expect 0-63)

    subnet2: 192.168.0.64: from 192.168.0.65~192.168.0.127

    subnet3: 192.168.0.128: from 192.168.0.129~192.168.0.191

    sunbet4: 192.168.0.192: from 192.168.0.193~192.168.0.255

    Best Regards,

    Anne


    Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Support, contact tnmff@microsoft.com.

    Wednesday, June 1, 2016 8:46 AM
    Moderator