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need help to solve a problem

Question
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My problem is the following sittuation:
I have this table in ACCESS database and i want help to get an SQL expression to solve the issue i explain:
this is the table i have, with 2 columns:
CODE count
0101 5
0101 8
0101 7
0305 8
0305 6
0305 1
So, what i want to do is to obtain the total of the count for each CODE
Example: for the CODE 0101 i have 5+8+7 = 20
So, i want to have an SQL expression that give me a table with the totals to each code
maybe its not complicated, but i am an inniciate with SQL, can you please help me with that?
Sunday, April 15, 2012 1:19 AM
Answers
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select code, sum([Count]) as [Total Count] from myTable GROUP BY [Code]
For every expert, there is an equal and opposite expert. - Becker's Law
My blog- Proposed as answer by Daniel_Steiner Sunday, April 15, 2012 8:58 AM
- Marked as answer by joca_santos Sunday, April 15, 2012 9:27 PM
Sunday, April 15, 2012 4:18 AM -
Hi,
Use Group by function http://msdn.microsoft.com/en-us/library/ms177673.aspx
SELECT CODE, SUM([count]) FROM tablename GROUP BY [CODE]
I hope this is helpful.Please Mark it as Answered if it answered your question
OR mark it as Helpful if it help you to solve your problem
Elmozamil Elamir Hamid
MyBlog
- Marked as answer by joca_santos Sunday, April 15, 2012 9:27 PM
Sunday, April 15, 2012 6:00 AM
All replies
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select code, sum([Count]) as [Total Count] from myTable GROUP BY [Code]
For every expert, there is an equal and opposite expert. - Becker's Law
My blog- Proposed as answer by Daniel_Steiner Sunday, April 15, 2012 8:58 AM
- Marked as answer by joca_santos Sunday, April 15, 2012 9:27 PM
Sunday, April 15, 2012 4:18 AM -
Hi,
Use Group by function http://msdn.microsoft.com/en-us/library/ms177673.aspx
SELECT CODE, SUM([count]) FROM tablename GROUP BY [CODE]
I hope this is helpful.Please Mark it as Answered if it answered your question
OR mark it as Helpful if it help you to solve your problem
Elmozamil Elamir Hamid
MyBlog
- Marked as answer by joca_santos Sunday, April 15, 2012 9:27 PM
Sunday, April 15, 2012 6:00 AM -
as explained above you will need to use the GROUP BY statement and a SUM() function in your SELECT clause
John
http://knowledgy.orgSunday, April 15, 2012 5:56 PM -
Thanks for your help
It works
joca_santos
Sunday, April 15, 2012 9:27 PM