none
Remove all text in a string after the first caret

    Question

  • I have a string that looks like this, for example:

    mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33

    I need to remove all of the text to the right of the first ^ (caret), including the ^. The text to the left of the first ^ will always be of unknown length, so I can't trim it based on that.

    I haven't been able to do this with .TrimEnd, or -replace, but maybe it could be done with regular expressions?

    Monday, August 08, 2011 7:49 PM

Answers

  •  

    1) "mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33" -split "\^")[0]
    
    2) "mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33" -replace "\^.+"
    
    3)$str = "mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33"
    $str.Substring(0,$str.IndexOf("^"))

     

    • Proposed as answer by Rich Prescott Monday, August 08, 2011 8:39 PM
    • Marked as answer by Cableman Tuesday, August 09, 2011 2:14 PM
    Monday, August 08, 2011 7:52 PM

All replies

  •  

    1) "mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33" -split "\^")[0]
    
    2) "mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33" -replace "\^.+"
    
    3)$str = "mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33"
    $str.Substring(0,$str.IndexOf("^"))

     

    • Proposed as answer by Rich Prescott Monday, August 08, 2011 8:39 PM
    • Marked as answer by Cableman Tuesday, August 09, 2011 2:14 PM
    Monday, August 08, 2011 7:52 PM
  • "mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33".split("^")[0]

    Karl


    My Blog: http://unlockpowershell.wordpress.com
    My Book: Windows PowerShell 2.0 Bible
    My E-mail: -join ("6B61726C6D69747363686B65406D742E6E6574"-split"(?<=\G.{2})",19|%{[char][int]"0x$_"})
    Monday, August 08, 2011 9:12 PM
  • $string = "mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33"
    ([regex]::match($string,"^[^^]+")).value
    [string](0..33|%{[char][int](46+("686552495351636652556262185355647068516270555358646562655775 0645570").substring(($_*2),2))})-replace " "
    Monday, August 08, 2011 9:22 PM
  • I like to use single quotes whenever expansion is not intended.
    In this case it might just be an issue of being more efficient.
     
    And, to be more efficient, there is no need to create more than two
    items in the array.
     
    'mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33'.split('^',2)[0]
     
    On 8/8/2011 4:12 PM, Karl Mitschke wrote:
    > "mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33".split("^")[0]
    >
     
    Monday, August 08, 2011 9:49 PM
  • Thank you to everyone who replied!  I appreciate the help. I will study the answers.

    This one probably makes the most sense to me, as it uses -replace and regular expresisons

    "mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33" -replace "\^.+"

    I know the a \ is needed before the ^, but I'm not sure about the use of .+

    Thanks,

    Ken

    Tuesday, August 09, 2011 2:13 PM
  • Hi Ken,

    The dot character in the regular expression matches ANY single character (caveats apply around newline characters....)

    The + is a repetition marker that says "repeat the proceeding match at least 1 (or more) times". So the pattern matches a caret followed by 1 or more characters.

     

    I'd be inclined to use an asterisk instead of the plus ('match 0 or more times') so you could match strings that don't have anything after the caret. Also, in PowerShell I would suggest using single quotes to enclose the regex unless you want variable expansion (you don't in this case). So, this does what you asked for - replaces the first caret and anything after it (even if there's nothing after it!)

    "mailserver004^sdfhsfsf^675756^fsdf.sqe2^#$WFSdd.33" -replace '\^.*'

    Cheers,

    Chris

    Tuesday, August 09, 2011 4:00 PM
  • The choice of .* instead of .+ is more important on a solution like the
    one below
     
    Contrast
     
    'mailserver004^' -split '\^.+' -join ''
    'mailserver004^' -split '\^.*' -join ''
     
    Tuesday, August 09, 2011 5:02 PM